8x^2+2x=136

Solution for 8x^2+2x=136 equation:

8x^2+2x=136

We move all terms to the left:

8x^2+2x-(136)=0

a = 8; b = 2; c = -136;
Δ = b2-4ac
Δ = 22-4·8·(-136)
Δ = 4356
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4356}=66$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-66}{2*8}=\frac{-68}{16}
=-4+1/4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+66}{2*8}=\frac{64}{16}
=4
$